Hello all.. Q about SCSI technote

lazyart

Hello all. I'm planning to sit for Core on 6/26. I was looking over the SCSI technotes and I see something that may be in error:

Wide
SCSI SCSI-2 (devices)16 (bus width)16 bits (bus speed)10 MHz (Through-put)10 MB/s

Wide SCSI as i understand is 16 bits (hence wide) but isn't the bus speed only 5 MHz? 10 MHz is "Fast" isn't it? That would make the Through-put at 10 MB/s.

For those trying to grasp the chart, divide the bus width by 8, then multiply that value by the bus speed.. this will give you through-put in MB/s.

Normal bus speed (MHz) = 5, Fast = 10, Ultra = 20.
Normal bus width (bits) = 8, Wide = 16.
SCSI-3 is always Wide.

Bus width is also the number of devices allowed on SCSI chain.

Am I correct?

Webmaster

Wide SCSI as i understand is 16 bits (hence wide) but isn't the bus speed only 5 MHz?

I've researched dosens of resources to double-check it, (as I did when I wrote it), but you are correct. The bus speed is only 5 MHz, and the Fast SCSI is 10 (as I said correctly in the foot note of the table) I think I mixed up values from the Fast SCSI-2 and Wide SCSI-2 row...



I apologize for the error, and any confusion it may have caused.