subnet question -- does not compute!?

mguy

192.168.100.66 /27

Find Valid Subnet, Broadcast, Valid hosts

/27 = 32 (block Size)
{0, 32, 64, 96... }
everyone ok so far?


A: (This is from lammle book which I believe has an error)

Valid Subnet: 192.168.100.32 (!!)
Broadcast address: 192.168.100.63 (!!)
Valid hosts: 192.168.100.33-63 (!!)

---

What's going on?

MrBrian

Well if that's what it says, then yea it's a mistake. With a /27 it's a block size of 32 like you said.

192.168.100.66/27 it would be:

subnet= 192.168.100.64
broadcast addr= 192.168.100.95
valid hosts= 192.168.100.65-94

martell1000

maybe its a typo and he meant 192.168.100.36 /27 which would match the answers

veritas_libertas

Yeah, unless I'm missing something it's completely wrong. Have you looked up the errata for your book?

Ltat42a

Here's his 7th edition errata page -

Wiley: CCNA Cisco Certified Network Associate Study Guide: Exam 640-802, includes CD-ROM, 7th Edition

MrBrian

Even if it was meant to be the 32 subnet, the valid hosts is still wrong..

It would be 192.168.100.33-62.. not 192.168.100.33-63 (63 is the broadcast addr for the subnet)