subnet question -- does not compute!?

mguymguy Posts: 167Member
192.168.100.66 /27

Find Valid Subnet, Broadcast, Valid hosts

/27 = 32 (block Size)
{0, 32, 64, 96... }
everyone ok so far?


A: (This is from lammle book which I believe has an error)

Valid Subnet: 192.168.100.32 (!!)
Broadcast address: 192.168.100.63 (!!)
Valid hosts: 192.168.100.33-63 (!!)

---

What's going on?

Comments

  • MrBrianMrBrian Posts: 520Member
    Well if that's what it says, then yea it's a mistake. With a /27 it's a block size of 32 like you said.

    192.168.100.66/27 it would be:

    subnet= 192.168.100.64
    broadcast addr= 192.168.100.95
    valid hosts= 192.168.100.65-94
    Currently reading: Internet Routing Architectures by Halabi
  • martell1000martell1000 Posts: 389Member
    maybe its a typo and he meant 192.168.100.36 /27 which would match the answers
    And then, I started a blog ...
  • veritas_libertasveritas_libertas Audentis Fortuna Iuvat Greenville, SC USAPosts: 5,733Member ■■■■■■■■■■
    Yeah, unless I'm missing something it's completely wrong. Have you looked up the errata for your book?
    Currently working on: Linux and Python
  • Ltat42aLtat42a Posts: 585Member ■■■□□□□□□□
  • MrBrianMrBrian Posts: 520Member
    Even if it was meant to be the 32 subnet, the valid hosts is still wrong..

    It would be 192.168.100.33-62.. not 192.168.100.33-63 (63 is the broadcast addr for the subnet)
    Currently reading: Internet Routing Architectures by Halabi
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