
Subnetting is an Evil Brain twister. Whomever the geniune was who created subnetting was EVIL Person. I hate Subnetting 500 different formulas to come a simple answer that a computer on calculator in a matter of second. The monster who puting subnetting on test in which the testor already nervous should beater to a pulse.... I HATE Subnetting
An Open Mind, Working to Get IT!:cheers:
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But seriously, it's not so hard once you've grasped the fundamentals. Now....until you get to the point where you fully understand it learning subnetting will be very painful. I was honestly about to stop studying for my ICND1 because I wasn't able to convert decimal numbers into binary.
Now I just laugh at myself for even thinking that and am glad I pushed through. I'm sure you will do the same!
Then, I took the Cisco Discovery/Exploration courses. The instructor spent about 3 days on subnetting, and everyone who hadn't already taken the Intro to Networking class was lost for most of the semester. We ended up having to teach our group mates how to subnet during lab time.
It really is a frustrating process, and everyone always says "you'll get it eventually", because they were once in your position. You WILL get it eventually, and when you do, you will wonder what other people are talking about when they say it's so hard to understand. Just stick with it!
a good hint is to print out a subnet table and use it everyday. after a few weeks you will just KNOW that a .248 mask is a /29 and has 8-2 usable hosts in it ....
1. Determine the number of networks and convert to binary.
2.Reserve bits in the subnet Mask and Find the Increment.
3.Use the Increment to find the Network Range.
Example: Network 195.5.20.0 Needs 50 netowrks
1. 50 = 00110010 or 6 bits
2. 255.255.255.00000011 or 255.255.255.252 /30 with an increment of 4
3. Ranges 195.5.20.0_______195.5.20.3
195.5.20.4_______195.5.20.7
195.5.20.8_______195.5.20.11
195.5.20.12______195.5.20.15
195.5.20.20______195.5.20.23 etc Simple
Example: 192.168.10.0= Network Address; 255.255.255.128=subnet mask. Therefore
1. How many subnets? 5 since 128 is 1 on (10000000), 2(2)- 2=126
2. What are the valid subnets? 256-128= 128 so our subnets are 0, 128
3. What are the broadcast address of each subnet 0 ,127
4. what are the valid hosts? 0 and 128
Subnet: 0 128
First host: 1 129
Last Host: 126 254I Broadcast 127 255 Understandable with a little work and can follow it through to some simple varable length.
But having to know all of this:
Subnet Mask CIDR Values
255.0.0.0 /8
255.128.0.0 /9
255.192.0.0 /10
255.224.0.0 /11
255.240.0.0 /12
255.248.0.0 /13
255.252.0.0 /14
255/254.0.0 /15
255.255.0.0 /16
255.255.128.0 /17
255.255.192.0 /18
255.255.224.0 /19
255.255.240.0 /20
255.255.248.0 /21
255.255.252.0 /22
255.255.254.0 /23
255.255.255.0 /24
255.255.255.128 /25
255.255.255.192 /26
255.255.255.224 /27
255.255.255.240 /28
255.255.255.248 /29
255.255.255.252 /30
And have plug it in every IP address on 90 minute test make not want to take the test. Oh , then after calculating the the ip addresses configure the switches and routers too..... AHHHHH
DOC
My suggestion would be to pick up a copy of Todd Lammles CCNA study guide if you haven't already done so and go through the chapter on subnetting. Thats how i got started with it all. At first i had no idea but after a few weeks of going through all the exercises again and again, it 'clicked'.
The key is when starting is to write EVERYTHING down, bit by bit. Grab a notebook and write everything down, the question, everything. That way it sticks in your brain. Spend half an hour to an hour each day just on subnetting and doing the exercises from the book. Rinse. Repeat. Rinse Repeat.
Know your subnet formulas...2^n for networks/subnets and 2^n-2 for hosts where n is the number of bits used
Know your powers of 2.
In your example network 195.5.20.0 needs 50 networks or subnets
What power of two will give you 50 subnets ?
2^4 = 16
2^5 = 32
2^6 = 64
195.5.20.0 is a class c address with a default subnet mask of 255.255.255.0 or in binary 11111111.11111111.11111111.00000000
So you will need to borrow 6 bits from the host portion of the address
So your subnet mask will be 255.255.255.252 or in binary 11111111.11111111.11111111.11111100
If you know your powers of two, then use your fingers to figure out the block size. It's that simple.
In all seriousness, I found Jeremy's explanation in the CBT Nuggets series to be really straightforward. Even with those, it still took some time (and practice) for it to really soak in. I kept on doing subnettingquestions.com questions for practice. If I got the answer wrong, I wouldnt move on until I figured out why I got it wrong. After about a solid weekend of doing this for a few hours each day, I could subnet within a minute!
Moral of story: doesnt matter how "bad" you think you are; with ENOUGH practice, you'll get it. Practice really does make perfect!!!
Certifications: CCENT; CCNA: R&S; Security+
Next up: RHCSA
Once you see it, you can't unsee it.
I used to stand in the shower and recite 8x 16x 32x 64x tables.
Subnet license plates and various number on bill board whilst driving
and now, I laugh to myself.
i think if i can do it anyone could,
keep at it and you will get there
I appreciate everything.
DOC
Once you see it, you can't unsee it.
Someone says /29 mask to me and my mind just jumps to 32 groups of 8 with 6 hosts each.
Plus, you have to love a good Matrix reference.
BUT, it takes skill to use a Matrix Reloaded reference.
"Damn it Morpheus, not everyone believes what you believe!"
"My beliefs do not require them to."
I knew you posted here Jeremy!