Beginner needs help here! :( Regarding Host
mindzfreak
Member Posts: 47 ■■□□□□□□□□
in CCNA & CCENT
Hey fellows out there, i really need ya guys help over here..im really confuse and lost i totally don't understand what is host or how to calculate host.. lets say, assuming i have a diagram of 4 routers. (router1 , router2 , router3, HQ)
Router1 has 56 host.
Router2 has 43 host.
Router3 has 29 host.
HQ has 3 host.
and the network for the diagram is 10.0.1.0 /16.
so its 10.0.1.0 (255.255.0.0)
How do i start off? im seriously lost because every one of the router has a host. so how do i do so ?
Router1 has 56 host.
Router2 has 43 host.
Router3 has 29 host.
HQ has 3 host.
and the network for the diagram is 10.0.1.0 /16.
so its 10.0.1.0 (255.255.0.0)
How do i start off? im seriously lost because every one of the router has a host. so how do i do so ?
Comments
-
sizeon Member Posts: 321I am not really sure what you are asking but a 255.255.0.0 net mask give you 65,534 host. You use the formula (2^n) - 2 where "n" is the number of host bits. The host bits are the "0" and the network bts are the "1".
-
MAC_Addy Member Posts: 1,740 ■■■■□□□□□□There's a few threads in here about Subnetting Made Easy. I highly recommend you read that. Also, you might want to get yourself a CCENT book to help with your learning.2017 Certification Goals:
CCNP R/S -
xbuzz Member Posts: 122A host is any end user device, such as a PC, Laptop, server, printer etc.
Router1 has 56 hosts means that router 1 has 56 pieces of end user equipment attached to it, each needing it's own IP address in the LAN.
So basically the question is asking you to split your network (10.0.1.0 /16) so that each subnets have enough space (ip addresses) for all their hosts. You start with the largest, so first piece will need 56 hosts, 2nd 43 hosts, 4rd 29 hosts and 4th 3 hosts.
A subnet can only be split up into these segments, 1, 2, 4, 8, 16, 32, 64, 128, 256. So you chose which segment encompasses your needed host range, without wasting too many Ip addresses.
So the first subnet which needs 56 hosts, you would use 64 etc. Hope this gets you started. -
Eildor Member Posts: 444mindzfreak wrote: »Hey fellows out there, i really need ya guys help over here..im really confuse and lost i totally don't understand what is host or how to calculate host.. lets say, assuming i have a diagram of 4 routers. (router1 , router2 , router3, HQ)
Router1 has 56 host.
Router2 has 43 host.
Router3 has 29 host.
HQ has 3 host.
and the network for the diagram is 10.0.1.0 /16.
so its 10.0.1.0 (255.255.0.0)
How do i start off? im seriously lost because every one of the router has a host. so how do i do so ?
It's all good asking for a bit of help but it seems as if you haven't the slightest clue... you need to learn the basics, and you need to learn how to subnet. -
MAC_Addy Member Posts: 1,740 ■■■■□□□□□□It's all good asking for a bit of help but it seems as if you haven't the slightest clue... you need to learn the basics, and you need to learn how to subnet.
Indeed. You've got to learn how to crawl before you can run.
I suggest you view this thread; http://www.techexams.net/forums/ccna-ccent/38772-subnetting-made-easy.html
This will help you learn subnetting.2017 Certification Goals:
CCNP R/S -
mindzfreak Member Posts: 47 ■■□□□□□□□□A host is any end user device, such as a PC, Laptop, server, printer etc.
Router1 has 56 hosts means that router 1 has 56 pieces of end user equipment attached to it, each needing it's own IP address in the LAN.
So basically the question is asking you to split your network (10.0.1.0 /16) so that each subnets have enough space (ip addresses) for all their hosts. You start with the largest, so first piece will need 56 hosts, 2nd 43 hosts, 4rd 29 hosts and 4th 3 hosts.
A subnet can only be split up into these segments, 1, 2, 4, 8, 16, 32, 64, 128, 256. So you chose which segment encompasses your needed host range, without wasting too many Ip addresses.
So the first subnet which needs 56 hosts, you would use 64 etc. Hope this gets you started.
Thanks my friend. i roughly get what u meant.. so if 56 hosts, i'd use 64. if 43 hosts, i'll use 64 also. if 29 hosts, i'll use 32.. am i correct? -
CodeBlox Member Posts: 1,363 ■■■■□□□□□□Here is a possible subnetting scheme that works:
Router 1 - 10.0.1.0 /26 Router 2 - 10.0.1.64 /26 Router 3 - 10.0.1.128 /27 HQ - 10.0.1.160 /29
Currently reading: Network Warrior, Unix Network Programming by Richard Stevens -
xbuzz Member Posts: 122mindzfreak wrote: »Thanks my friend. i roughly get what u meant.. so if 56 hosts, i'd use 64. if 43 hosts, i'll use 64 also. if 29 hosts, i'll use 32.. am i correct?
Yep, that's right.
CodeBlox posted the right answers there also.