Need technique for subnetting,CDIR and VLSM please!
teastain
Member Posts: 3 ■□□□□□□□□□
Hi,
Would some kind soul help me out with a practical method to working out the subnetting elements for the 70-291 exam? I have a mental block with this stuff , and cannot make any sense out of the resources on the net.
Does anyone have a good method ?
Would some kind soul help me out with a practical method to working out the subnetting elements for the 70-291 exam? I have a mental block with this stuff , and cannot make any sense out of the resources on the net.
Does anyone have a good method ?
Comments
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fayo79 Member Posts: 9 ■□□□□□□□□□Easiest method would be to convert to binary the IPs to binary. And also use the 128, 64, 32, 16, 8, 4, 2, 1 table and just write it down on top.
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chris.brown Member Posts: 8 ■□□□□□□□□□say you have mask of 192.168.1.2/20
your mask has 20 bits. 255.255.240.0
2 to the power of the number of masked bits (4) cos thats how many come after the 255.255. -2 = number of subnets
so (2 to the power of 4) -2 = 14 subnets
do the same for unmasked bit to find the number of hosts per subnet.
(2 to the power of twelve -2) -2 = 4094 hosts per subnet. -
jmc724 Member Posts: 415Theres an old book from exam cram called tcp/ip, it deals with all subnets and understanding them. It was one of those exams that were required for nt4 mcse.
You can find this book at a second hand book store or e*ay...What next? -
PawNtheSandman Member Posts: 47 ■■□□□□□□□□chris.brown wrote:say you have mask of 192.168.1.2/20
your mask has 20 bits. 255.255.240.0
2 to the power of the number of masked bits (4) cos thats how many come after the 255.255. -2 = number of subnets
so (2 to the power of 4) -2 = 14 subnets
do the same for unmasked bit to find the number of hosts per subnet.
(2 to the power of twelve -2) -2 = 4094 hosts per subnet.
Thanks, that explained it alot better than my books.
But once I do that, how do I determine the exact IP addresses to assign for the network?Currently Studying: CCNA