Class B subnettting
hassantalal785
Member Posts: 47 ■■□□□□□□□□
in CCNA & CCENT
Here is a question :
Given a class B network of 155.44.200.0, what mask could be used to provide 15 networks each supporting 120 users :
A 255.255.252.0
B 255.255.248.0
C 255.255.240.0
D 255.255.255.128
E 255.255.255.240
The correct answer is "C".
But i think option "A","B","C"and "D" are correct
Because if i want 15 networks so i will use 4 network bits and for 120 users 7 host bits .So if i use 255.255.252.0 (Option A) i will have Network Bits = 6 and Host bits =10 .If i use 255.255.248.0 i have Network Bits = 5 and Host bits =11 .For 255.255.240.0 i have Network Bits = 4 and Host bits =12 and for 255.255.255.128 i haveNetwork Bits = 9 and Host bits =7.
I know i am missing something but cant figure out what.Kindly explain this in detail.
Given a class B network of 155.44.200.0, what mask could be used to provide 15 networks each supporting 120 users :
A 255.255.252.0
B 255.255.248.0
C 255.255.240.0
D 255.255.255.128
E 255.255.255.240
The correct answer is "C".
But i think option "A","B","C"and "D" are correct
Because if i want 15 networks so i will use 4 network bits and for 120 users 7 host bits .So if i use 255.255.252.0 (Option A) i will have Network Bits = 6 and Host bits =10 .If i use 255.255.248.0 i have Network Bits = 5 and Host bits =11 .For 255.255.240.0 i have Network Bits = 4 and Host bits =12 and for 255.255.255.128 i haveNetwork Bits = 9 and Host bits =7.
I know i am missing something but cant figure out what.Kindly explain this in detail.
Comments
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NetworkVeteran Member Posts: 2,338 ■■■■■■■■□□hassantalal785 wrote: »Here is a question :
Given a class B network of 155.44.200.0, what mask could be used to provide 15 networks each supporting 120 users :
2^3 = 8, 2^4 = 16. You need 4+ subnet bits to support 15+ subnets.
2^6-2 = 62, 2^7-2 = 126. You need 7+ host bits to support 120+ users.
A class B network mask eats up 16 bits.
a) A - 255.255.252.0 - A /22 w/ 16 net bits, 6 subnet bits, and 10 host bits. Pass.
b) B - 255.255.248.0 - A /21 w/ 16 net bits, 5 subnet bits, and 11 host bits. Pass.
c) C - 255.255.240.0 - A /20 w/ 16 net bits, 4 subnet bits, and 12 host bits. Pass.
d) D - 255.255.255.128 - A /25 w/ 16 net bits, 9 subnet bits, and 7 host bits. Pass.
e) E - 255.255.255.240 - A /28 w/ 16 net bits, 12 subnet bits, and 4 host bits. Fail.The correct answer is "C".
But i think option "A","B","C"and "D" are correct -
hassantalal785 Member Posts: 47 ■■□□□□□□□□The given Class B address is 155.44.200.0 .Wouldn't 200 in the third octet play in role in determining the mask ?
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NetworkVeteran Member Posts: 2,338 ■■■■■■■■□□The given Class B address is 155.44.200.0 .Wouldn't 200 in the third octet play in role in determining the mask ?
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hassantalal785 Member Posts: 47 ■■□□□□□□□□NetworkVeteran wrote: »155.44.0.0/8 is a class B network. 155.44.200.0 is not.
Can a Class B address have a /8 mask ? -
NetworkVeteran Member Posts: 2,338 ■■■■■■■■□□hassantalal785 wrote: »Can a Class B address have a /8 mask ?
http://www.aturtschi.com/whois/networks.html
As you'll notice, 155.44.0.0 is listed. 155.44.200.0 is not.
155.044.0.0
Houghton Mifflin Company
NET-HMCO-NET
<removed>
Boston, MA 02108
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chopsticks Member Posts: 389I think this question is incorrectly asked because there are more than one answer that fit the requirement.