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sting_224 wrote: » The way I understand it is like this: 192.168.84.0 (class c) with subnet mask 255.255.255.0 (11111111.11111111.11111111.00000000) Since we want 19 subnets with up to 4 host, we'll take 5bits from the host portion our subnet mask (The part with all 0s) This gives us 2^5 = 32 subnets, if we had taken 4 bits it'll give us 2^4= 16 subnets (not enough) So the subnet mask we'll use is 255.255.255.248 (11111111.11111111.11111111.'11111'000)
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