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Node Man wrote: » I feel that I have mastered the subject as I nearly always get the right answer. However I am very slow. And I use excel to help reach my answers
boredgamelad wrote: » Sorry to be blunt . . . .Learn it the hard way and you'll appreciate it in the long run.
WiseWun wrote: » Too much memorizing can lead to confusion. Start by practicing on paper and not Excel. The subnet calculator should only be used for verification if you know what your doing. What I normally do is write down these values (128.64.32.16.8.4.2.1) and this helps me figure out the mask, block size, ip range,etc. The left side is network and right is host. So if the question requires 20 hosts, I would borrow 5 bits starting from the right and draw a line. See example. 192.168.10.0, requirement is 20 hosts 128.64.32.|16.8.4.2.1 As you can see from above, my block size/increment is 32 (the # on your left side thats closest to the | character) I can also figure out the subnet mask by adding all the values on the left of the | character, 128+64+32=224. To get the IP range, network and broadcast address, use the block size of 32 starting from network zero. 192.168.10.0 - 192.168.10.31 192.168.10.32 - 192.168.10.63 192.168.10.64 - 192.168.10.95 192.168.10.96 - 192.168.10.127 192.168.10.128 - 192.168.10.159 192.168.10.160 - 192.168.10.191 192.168.10.192 - 192.168.10.223 192.168.10.224 - 192.168.10.255 There are 8 networks above starting with subnet zero. 8 because we borrowed 5 bits for the hosts therefore 3 bits remain for the network portion, 2^3=8. The broadcast address is always the last odd number in the range so .31, .63 are both broadcasts address within their respective networks. The first usable IP address range for subnet 6 is 192.168.10.161 - 192.168.10.190 I hope this was informative. Keep practicing until you nail it and stick to one method for the time being.
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