About Summarize Static Route...

Hello,

This is my 1st post

I am summarizing (5) Networks with the ff.

IP's
a=10.19.32.0
b=10.19.48.0
c=10.19.40.0
d=10.19.56.0
e=10.19.57.0

Binary's
a=00001010.00010011.001 00000.00000000
b=00001010.00010011.001 10000.00000000
c=00001010.00010011.001 01000.00000000
d=00001010.00010011.001 11000.00000000
e=00001010.00010011.001 11001.00000000
______________________________________
10 . 19 . ???? . 0

What will be the 3rd octet?

I'm having hard time to compute or summarize IP, Is there any short cut or Magic like Subnetting???

Before I forgot, Should I include the CIDR in summarizing?

anyways here they're ff CIDR :

a= /21
b= /23
c= /22
d= /24
e= /30

Thanks and very much appreciated!!

-Arnold

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Comments

gbdavidx

0?

10.19.0.0, i believe, or it could be 10.19.32.0 not 100% haven't studied summarization

DANMOH009

10.19.32.0 is right,

Have you read up on route sum ard?

Subnetting Made Easy And Other Cisco Tidbits: Route Summarization

try this site, once doing that you should be fine knowing the prefix also.

theodoxa

10.19.32.0/19

Address Range: 10.19.32.1 - 10.19.63.254

theodoxa

Subnets [to be summarized]:

10.19.32.0/21
10.19.40.0/22
10.19.48.0/23
10.19.56.0/24
10.19.57.0/30

Address Ranges:

10.19.32.1 - 10.19.39.254
10.19.40.1 - 10.19.43.254
10.19.48.1 - 10.19.49.254
10.19.56.1 - 10.19.56.254
10.19.57.1 - 10.19.57.2

Additional Subnets that could be added:

10.19.44.0/22
10.19.50.0/23
10.19.52.0/22
10.19.57.4/30
10.19.57.8/29
10.19.57.16/28
10.19.57.32/27
10.19.57.64/26
10.19.57.128/25
10.19.58.0/23
10.19.60.0/22

pogue

Easy way to do a problem like this is to go to the "different" octet, and keep in mind you will only count in increments that fit fully within the 128/64/32/16/8/4/2 bit range.

Your networks - 32-57, cannot be covered between the lower to upper range by 16... (32+16=48, 56.0 and 57.0 being left out..)
They can be covered by a 32.... (32+32=64, which includes all the ranges in the "different" octet..)

Now, take this 32 number you have arrived at, and subtract it from 256. (256-32=224)

You summary subnet mask is 255.255.224.0. (This is a /21) Starting at 10.19.32.0/21...

Ocassionally, you will have to subnet where the lower network is not so obvious. All you have to do is take the lowest network you are given, and add 2/4/8/16/32/64/or 128 to it until you fully cover the range of networks. Whatever number you arrive at, multiply it until you get the largest number you can get that is smaller than your lower range.

This is probably not coming across as thta easy to understand, but it should become easier if you look on Google for subnetting tips and tricks. This same method I use is explained a number of different ways.

Russ