Question relating to IP

FYou

I belong to network 293.200.148.0/22. Is it possible to have such a network address?

If I send a ping to 293.200.151.101/22. Is it going through my default gateway?

what is the size of my network? and is it a subnet?

My guess is no, no, no, and 1024? is it correct??

SecurityThroughObscurity

Yes, I suppose.
It's a subnet.

droolmonkey

ip addresses are 4 octets. 1111111 is 255 so max is 255.255.255.255 (actually for all intents and purposes of net+ it stops at 223.255.255.255).

Ping isnt going anywhere. if you had a valid ip address then yes it would because the /22 is the subnet and the subnet you are pinging is different from your own, therefore it has to go through the gateway

32-22=10 so 2^10 = 1024 = size



im tired and guessing at this point so someone check me, but i think its right.

NetworkVeteran

I belong to network 293.200.148.0/22. Is it possible to have such a network address?

No.

If I send a ping to 293.200.151.101/22. Is it going through my default gateway?

No.

what is the size of my network? and is it a subnet?

Well, since this nonsensical address is at least 36 bits long to represent the value "293" (four groups of nine bits each), you have at least 36-22 =14 host bits. That's approximately ~16,000 hosts.

NetworkVeteran

droolmonkey wrote: »

if you had a valid ip address.. 32-22=10 so 2^10 = 1024 = size

Right on.

Gngogh

8 bits is the maximum u can have per octet. u have to see this in binary to understand why ip address dont have decimal numbers bigger than 255.