Subnetting Question, ANY help would be great!
SubnetNoob
Member Posts: 9 ■□□□□□□□□□
in CCNA & CCENT
Hey guys I have started my first day of a networking course at my local college and I am a bit rusty on my subnetting.
I have been given a scenario...Using 200.100.50.128/26 as your address base, create as many point-to-point links as possible and assign the addresses to each interface. Following I have a Packet tracer file which if I could figure out the Subnetting will not have a problem configuring. I believe my instructor told us that this is VLSM, however im unsure how to tackle the subnetting of VLSM without having specifications such as number of host per subnet needed.
Im kind of lost and any help would be appreciated thanks.
I have been given a scenario...Using 200.100.50.128/26 as your address base, create as many point-to-point links as possible and assign the addresses to each interface. Following I have a Packet tracer file which if I could figure out the Subnetting will not have a problem configuring. I believe my instructor told us that this is VLSM, however im unsure how to tackle the subnetting of VLSM without having specifications such as number of host per subnet needed.
Im kind of lost and any help would be appreciated thanks.
Comments
-
networker050184
Mod Posts: 11,962 Mod
If the instructor wants you to make point-to-point links I'm assuming /30s or /31s is what he's looking for. You should probably ask your instructor for clarification though rather than relying on guesses here.An expert is a man who has made all the mistakes which can be made. -
SubnetNoob
Member Posts: 9 ■□□□□□□□□□
I have been trying too, these profs dont respond to emails quick. I have looked at a friend of mines answer but hes not here to explain so im still a bit confused he has
200.100.20.129/27
200.100.20.130/27
200.100.20.161/27
200.100.20.162/27
does this look correct? -
networker050184
Mod Posts: 11,962 Mod
No that doesn't look correct to me, but I'm not certain what the requirements are. If it is simply to make as many p2p links as possible then that isn't how you'd do it.An expert is a man who has made all the mistakes which can be made.
-
SubnetNoob
Member Posts: 9 ■□□□□□□□□□
Yes the requiements state exac this
200.100.50.128/26 create as many point-to-point links as possible and assign addresses to each interface. ( The Packet tracer is only of three router connnected by serial cables ). If it was simply as many point to point links then what would it be OR how should i start this? -
networker050184
Mod Posts: 11,962 Mod
As many p2p links as possible would be to break this into /31s.
200.100.50.128/31
....
....
....
200.100.50.190/31
I have no idea if that is what your instructor is looking for though which is why I highly recommend you get some clarification.An expert is a man who has made all the mistakes which can be made. -
SubnetNoob
Member Posts: 9 ■□□□□□□□□□
Hello an update is that he said point to point links means 2 host per subnet...Does this make more sense ? If so what would the subnet.
-
TechGuru80
Member Posts: 1,539 ■■■■■■□□□□
I put this in your other post...
I am assuming that is suppose to be 2 hosts per network right? You cannot use that subnet mask for only 2 hosts per network. So subnet mask for the new networks is 255.255.255.252 (128 + 64 + 32 + 16 + 8 + 4), borrowing 6 bits so /30 (24 + 6). That means your networks will = 2 ^ 6, and range per network will = 2 ^ (8 - 6). 64 networks would be a full octet so cut it in half because we are at 128, 32 networks. Each range has 4 addresses, first = network, last = broadcast, so two hosts per network.
That means 128 is the start of your first range...
128-131
132-135
136-139
etc. -
SubnetNoob
Member Posts: 9 ■□□□□□□□□□
Ok thanks this makes more sense to me..... exactly what do you mean since we are at 128 cut in it in half?
Also a following question which im also a bit confused on, Using 195.165.85.96/27 as your initial base create as many point to point links as possible and assign the address to each interface.
