IPv6 Prefix Subnet abbreviation for a /52 mask

Andrew Newman

Hi,
I'm looking at a practice question that reduces FD00:0001:0001:0001:0200:00FF:FE00:0001 /52 to FD00:1:1::/52.
I am wondering why it shouldn't be FD00:1:1:0000::/52
I do understand that you mostly leave out quartets that are all 0's, but I thought that the rules were different when the boundary was not at the edge of a quartet.
Any explanation gratefully received.
thanks
Andrew

Jon_Cisco

I am not great with IPv6 but I don't know of a requirement to write out 0s if the network is subnetted there.
If I was asked to guess at the answer I would have picked the FD00:1:1:: answer.

mikeybinec

Rick Graziani, who is a Cisco Netacad author has a new book that I bought that explains IPv6.. Also has vids on his site and lot's of good links

IPv6

EdTheLad

So each character is hex and represents 4 bits, 52/4 =13 , so the network portion is 52 bits which means the host portion is 128-52 = 76 bits. As per ipv4 when dealing with subnets, make the host portion all zeros.

Therefore network address is FD00:0001:0001:0000:0000:0000:0000:0000/52, in ipv6 you can replace groups of 0000:0000 with :: , therefore the network address is FD00:0001:0001::/52