vlsm
hi require help can anyone help me plz ?
Using the 10.0.0.0/8 network, subnet the network to allow for 2040
usable subnets. Using subnet #1162, subnet the network to allow
for 30 usable subnets. Using your answer from the previous
calculation, subnet the subnet #18 to allow for 6 usable subnets.
Hint: if done correctly, the subnet mask that is required for any of
the final subnets will be a /27.
Using the 10.0.0.0/8 network, subnet the network to allow for 2040
usable subnets. Using subnet #1162, subnet the network to allow
for 30 usable subnets. Using your answer from the previous
calculation, subnet the subnet #18 to allow for 6 usable subnets.
Hint: if done correctly, the subnet mask that is required for any of
the final subnets will be a /27.
Comments
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networker050184
Mod Posts: 11,962 Mod
Why don't you show us what you came up with and we can point you in the right direction. We aren't here to do your homework for you.An expert is a man who has made all the mistakes which can be made. -
lalodhi
Registered Users Posts: 4 ■□□□□□□□□□
I have got
first useable address 10.0.0.1
last useable address 10.0.7.254
broadcast address 10.0.7.255
next network id 10.0.8.0/21
i dont knw how i can solve it for subnet 1162 for 30 hosts.
10.0.0.1 - 10.0.7.254
10.0.7.255
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lalodhi
Registered Users Posts: 4 ■□□□□□□□□□
the point im stucked is using subnet 1162 and 18. Plz guide me how to do it i will do it myself
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Heero
Member Posts: 486
For the first part, you are being asked to divide the 10.0.0.0/8 network into 2048 SUBNETS, not a single subnet with 2048 hosts.
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lalodhi
Registered Users Posts: 4 ■□□□□□□□□□
no one agree to help me. its been a day i havnt got such a clue to get it solve.For the first part, you are being asked to divide the 10.0.0.0/8 into 2048 SUBNETS, not a single subnet with 2048 hosts.
anyway special thanks to heero for guiding me in right direction. -
Scorp6
Member Posts: 56 ■■□□□□□□□□
The formula required is 2^n-2 where n is number of bits borrowed for either subnets or hosts. In this case 2^11 gives you 2048 which is as close as you can get to your requirement of 2040 subnets. This yields a subnet mask of /19 or 255.255.224.0 for your required 2040 subnets. I will let you continue from there.
