vlsm

lalodhilalodhi ■□□□□□□□□□ Posts: 4Registered Users ■□□□□□□□□□
hi require help can anyone help me plz ?
Using the 10.0.0.0/8 network, subnet the network to allow for 2040
usable subnets. Using subnet #1162, subnet the network to allow
for 30 usable subnets. Using your answer from the previous
calculation, subnet the subnet #18 to allow for 6 usable subnets.
Hint: if done correctly, the subnet mask that is required for any of
the final subnets will be a /27.

Comments

  • networker050184networker050184 Mod Posts: 11,962Mod Mod
    Why don't you show us what you came up with and we can point you in the right direction. We aren't here to do your homework for you.
    An expert is a man who has made all the mistakes which can be made.
  • lalodhilalodhi ■□□□□□□□□□ Posts: 4Registered Users ■□□□□□□□□□
    I have got
    first useable address 10.0.0.1
    last useable address 10.0.7.254
    broadcast address 10.0.7.255
    next network id 10.0.8.0/21
    i dont knw how i can solve it for subnet 1162 for 30 hosts.



    10.0.0.1 - 10.0.7.254
    10.0.7.255

  • lalodhilalodhi ■□□□□□□□□□ Posts: 4Registered Users ■□□□□□□□□□
    the point im stucked is using subnet 1162 and 18. Plz guide me how to do it i will do it myself
  • HeeroHeero Posts: 486Member
    For the first part, you are being asked to divide the 10.0.0.0/8 network into 2048 SUBNETS, not a single subnet with 2048 hosts.
  • lalodhilalodhi ■□□□□□□□□□ Posts: 4Registered Users ■□□□□□□□□□
    Heero wrote: »
    For the first part, you are being asked to divide the 10.0.0.0/8 into 2048 SUBNETS, not a single subnet with 2048 hosts.
    no one agree to help me. its been a day i havnt got such a clue to get it solve.
    anyway special thanks to heero for guiding me in right direction.
  • Scorp6Scorp6 ■■□□□□□□□□ Posts: 56Member ■■□□□□□□□□
    The formula required is 2^n-2 where n is number of bits borrowed for either subnets or hosts. In this case 2^11 gives you 2048 which is as close as you can get to your requirement of 2040 subnets. This yields a subnet mask of /19 or 255.255.224.0 for your required 2040 subnets. I will let you continue from there.
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