Network vs Host question

Handbrake

KPWright wrote: »

Handbrake, If you don't mind I'll take a stab at this and maybe somebody can check me on it.

99.0.0.0 is a class A network so the first octet is dedicated. The remaining 24 bits are available to identify subnets / hosts. The 17 bit mask includes the 8 bits which identify the class A as well as 9 more that are "borrowed" to identify possible subnets. The number of available subnets is therefore 2^9 = 512.

How'd I do?

yea can u break it down to binary for me

KPWright

Handbrake wrote: »

yea can u break it down to binary for me

Not sure what you are looking for. Try this:

The network address is 99.0.0.0 or 01100011.00000000.00000000.00000000

The class A network reserves the first octet leaving 24 bits for subnet / host addresses xxxxxxxx.00000000.00000000.00000000

The 17 bit mask includes the first octet and 9 additional bits xxxxxxxx.11111111.10000000.00000000

These 9 bits constitute the available range of subnet addresses (where host portion is all zeros) xxxxxxxx.00000000.00000000.00000000 thru xxxxxxxx.11111111.10000000.00000000

So the max number of subnets is 2^9 = 512 ranging from
99.0.0.0 --> 01100011.00000000.00000000.00000000 thru
99.255.128.0 --> 01100011.11111111.10000000.00000000

Each subnet would have a maximum of (2^15)-2 = 32766 host addresses.
01100011.xxxxxxxx.x0000000.00000001 thru
01100011.xxxxxxxx.x1111111.11111110

It's a big network

tech-airman

Handbrake wrote: »

255.255.255.0

Handbrake,

Apply the subnet mask of 255.255.255.0 to the IP address 192.168.1.33 and what do you get?

DerekAustin26

As I always understood it.. Class A Is just safer because less networks = less vulnerability to attack. More pc's with less networks.

Class B & C have more networks to pc ratio, meaning they are more susceptible to attacks from other networks..

Anyone correct me on this if this is the wrong logic?

DerekAustin26

Out in the real world How many switches and router do I need to deal with 8190 hosts? How would you setup a network with these many hosts..?

I've looked at diagrams from within a NOC. You have your Core Routers which can be connected to quite a few big Distribution Switches. Each Distro switch can connect to at least 100 different other nodes and some of those nodes could be Access Switches which can have up to 24 ports. Now this kinda gives you an idea of how the numbers can add up.

Example: CORE ROUTER connected to 10 Distribution switches, all 10 of them connected to 100 other switches or pcs. Lets say out of each 100 there were at least 10 switches connected to 10 other nodes. That'd be at least 100 nodes just for the Access Switches alone. Then add that to the 10 distro switches w 100 ports (Cuz usually they have about 10 blades in them with about 12 ports) 100 x 10 = 1000. So we have approx. 1100 nodes connected to that 1 Core Router. This is why Core Routers have to be redundant & fault taulerant, because huuge enterprise networks can go down and cause major outages if something happens to that Core router's power supplies or supervisor console. This help?
ANyone feel free to comment on this.. I'm no expert either, but this is my understanding from my experience.

Handbrake

tech-airman wrote: »

handbrake,

apply the subnet mask of 255.255.255.0 to the ip address 192.168.1.33 and what do you get?

192.168.1.0

192.168.1. 0 x x x
255.255.255.0 11111111 11111111 11111111 00000000

2^8 = 256 - 2 = 254 Hosts
2^24 = 16777216 - 2 16777214 Networks

192.168.1.1 thu 192.168.1.254 Host
0 Subnet?

Handbrake

DerekAustin26 wrote: »

Out in the real world How many switches and router do I need to deal with 8190 hosts? How would you setup a network with these many hosts..?

I've looked at diagrams from within a NOC. You have your Core Routers which can be connected to quite a few big Distribution Switches. Each Distro switch can connect to at least 100 different other nodes and some of those nodes could be Access Switches which can have up to 24 ports. Now this kinda gives you an idea of how the numbers can add up.

Example: CORE ROUTER connected to 10 Distribution switches, all 10 of them connected to 100 other switches or pcs. Lets say out of each 100 there were at least 10 switches connected to 10 other nodes. That'd be at least 100 nodes just for the Access Switches alone. Then add that to the 10 distro switches w 100 ports (Cuz usually they have about 10 blades in them with about 12 ports) 100 x 10 = 1000. So we have approx. 1100 nodes connected to that 1 Core Router. This is why Core Routers have to be redundant & fault taulerant, because huuge enterprise networks can go down and cause major outages if something happens to that Core router's power supplies or supervisor console. This help?
ANyone feel free to comment on this.. I'm no expert either, but this is my understanding from my experience.

Per whole network you can only have one core router ? or can you trunk core router?

fieldmonkey

Forsaken_GA wrote: »

To try and simplify this a bit -

A host is an endpoint, and a network is a logical grouping of hosts. Think of it like a baseball team - the network identifier tells you the team is the Detroit Tigers, and number 35 identifies Justin Verlander.

Great Analogy!

Do you mind if I steal this and tuck it away for use later?

tech-airman

Handbrake,

Handbrake wrote: »

192.168.1.0

This is all I wanted. So to answer your question of "Network vs. Host..."

Host
192.168.001.|033

Sub/Network Mask
255.255.255.000

Network
192.168.001.|000

So in review, the network address is what you get when you apply the network mask to the host address. The host address is the network address plus the host bits on the far right, in this case 192.168.1.0 + 0.0.0.33 = 192.168.1.33. Just so you know, the '|' above marks the network boundary. Does this make sense? Does this help?

Handbrake wrote: »

192.168.1. 0 x x x
255.255.255.0 11111111 11111111 11111111 00000000

2^8 = 256 - 2 = 254 Hosts
2^24 = 16777216 - 2 16777214 Networks

192.168.1.1 thu 192.168.1.254 Host
0 Subnet?