urgent Questions ??
rezq
Registered Users Posts: 2 ■□□□□□□□□□
in CCNA & CCENT
hello,
please I have these questions and need the answers>>>
Q1: An ISP is granted a CIDR block of addresses starting with
120.60.4.0/22. The ISP wants to distribute these blocks to 100 organizations with
each organization receiving 8 addresses only. Design the sub-blocks and give the
slash notation for each sub-block. Find out how many addresses are still available
after these allocations.
Q2: In some situations, a subset of the more specific routes needs to be
advertised in addition to the aggregate? Explain why with the help of an example.
the fast response will be highly appreciated..
please I have these questions and need the answers>>>
Q1: An ISP is granted a CIDR block of addresses starting with
120.60.4.0/22. The ISP wants to distribute these blocks to 100 organizations with
each organization receiving 8 addresses only. Design the sub-blocks and give the
slash notation for each sub-block. Find out how many addresses are still available
after these allocations.
Q2: In some situations, a subset of the more specific routes needs to be
advertised in addition to the aggregate? Explain why with the help of an example.
the fast response will be highly appreciated..
Comments
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networker050184
Mod Posts: 11,962 Mod
We aren't going to do your work for you. Why don't you tell us what you think the answers are and we can help point you in the right direction if you are off.An expert is a man who has made all the mistakes which can be made. -
Jon_Cisco
Member Posts: 1,772 ■■■■■■■■□□
sounds like your on your way to class without your assignment
-
xnx
Member Posts: 464 ■■■□□□□□□□
I've never understood why people would want to **** themselves...Getting There ...
Lab Equipment: Using Cisco CSRs and 4 Switches currently -
rezq
Registered Users Posts: 2 ■□□□□□□□□□
I do understand your point of view
..
So to get the ball rolling I want to negotiate the answer of the first question.
A1. the total number of addresses is (2)10 = 1024 addresses.
Each group needs 8 addresses only. That means the prefix length is 32-3=29 so that the slash notation will be /29.
The first sub-block 120.60.4.0/29 to 120.60.4.7/29
The second sub-block 120.60.4.8/29 to 120.60.4.15/29
.
.
.
.
Te addresses which still available is 1024 - (8*100)= 224 addresses.
Please tell me that this is wright and if so , give me a help with the second Q.:D
thank you all .. -
HAMP
Member Posts: 163
Each group needs 8 addresses only:
The first sub-block 120.60.4.0/29 to 120.60.4.7/29
The second sub-block 120.60.4.8/29 to 120.60.4.15/29
With cisco you have to pay close attention to the wording of a question. Such as usable host vs subnet size.
When you say each organization needs 8 addresses, I’m thinking you mean 8 usable ip address for 8 individual host.
The ranges you have will not cover 8 host, because 120.60.4.0 is the network, and 120.60.4.15 is the broadcast.
